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1,101 PointsI need help in code challenge
Python 3.6.3 |Anaconda, Inc.| (default, Oct 15 2017, 03:27:45) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> def disemvowel(word):
... word_1 = list(word)
... for words in word_1:
... if "a" in words:
... words.remove("a")
... if "A" in words:
... words.remove("A")
... if "i" in words:
... words.remove("i")
... if "I" in words:
... words.remove("I")
... if "u" in words:
... words.remove("u")
... if "U" in words:
... words.remove("U")
... if "e" in words:
... words.remove("e")
... if "E" in words:
... words.remove("E")
... if "o" in words:
... words.remove("o")
... if "O" in words:
... words.remove("O")
... word_2 = ",".join(words)
... print(word_2)
...
>>> disemvowel("HUBxcbeYq")
H
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 15, in disemvowel
AttributeError: 'str' object has no attribute 'remove'
>>>
def disemvowel(word):
word_1 = list(word)
for words in word_1:
if "a" in words:
words.remove("a")
if "A" in words:
words.remove("A")
if "i" in words:
words.remove("i")
if "I" in words:
words.remove("I")
if "u" in words:
words.remove("u")
if "U" in words:
words.remove("U")
if "e" in words:
words.remove("e")
if "E" in words:
words.remove("E")
if "o" in words:
words.remove("o")
if "O" in words:
words.remove("O")
word_2 = ",".join(words)
print(word_2)
1 Answer
Steven Parker
231,269 PointsThe loop iterates through the list "word_1" and separates each letter into a string named "words". But strings do not have a "remove" method. Did you intend to perform that method on the list ("word_1") instead?
A few other hints:
- altering a list while iterating on it can cause items to be skipped
- you can't "join" a string, did you mean to do that on the list?
- joining with a "," will not rebuild the word, but will create a string of comma-separated letters