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Python Python Collections (Retired) Dictionaries Word Count

reza sajadian
reza sajadian
718 Points

I need help with my quiz

My quiz is :

Create a function named word_count() that takes a string. Return a dictionary with each word in the string as the key and the number of times it appears as the value.

and what I have created is:

def word_count(): stn_my_str = my_str.lower() mylist = stn_my_str.split() replist = mylist[:] # Keeps the original listed string untouched for word in replist: while True: replist1 = replist[:] if word in replist1: replist1.remove(word) count += 1 continue else: break word_dict['word'] = count count = 0 break

3 Answers

Bart Bruneel
Bart Bruneel
27,212 Points

Hello reza,

It is a bit difficult to see how your code works because it is not formatted right, but I'll give this a shot. Remember you can format the code by typing it inside python . Check the markdown cheatsheet for extra help. Or you can take a snapshot of your workspace if you are coding the challenge in workspaces. Couple of things you could fix.

  • The function word_count should take a string as argument. For the moment no arguments are put into the function. You can fix this like this.
def word_count(string):
  • The lowercasing and the splitting of the string is done right.
  • Then you create a list instead of a dictionary. You can create a dictionary as follows:
my_dict= {}
  • Then you should loop over the words in the list and put them inside the dictionary. Use a for-loop.
for word in mylist:
  • If the word is already inside of the dictionary as a key, we should add one to it's value.
if word in mydict:



In the end the dictionary should be returned.

Happy coding!

reza sajadian
reza sajadian
718 Points

Sorry, the previous message was not formatted right. Here is what I have written: Hope it helps to understand my main problem.

string = 'life is life and my life is a good life' my_dict = {}

def word_count():

stn_string = string.lower() mylist = stn_string.split() replist = mylist[:] # replist(as of replicated list) Keeps the original listed string intact for word in replist: while True: if word in replist: replist.remove(word) word_dict[word] += 1 continue else: break break return(word_dict)

Bart Bruneel
Bart Bruneel
27,212 Points

Hey Reza,

There is no need to specify a string of your own. When checking your code, the challenge will pass a string to the function. Specifying your own string will probably give problems. Also remember to pass an argument to the function (see my previous post). Also, the my_dict needs to be specified inside of the function. Two other remarks:

  • it is not needed to make a replica of the list and to remove the words from the replica as you loop over the words. You can just loop over the words in the original list (mylist).

  • There is also no need to add a while-loop. For the moment your code will work as follows:

    • It will go into the for-loop.
    • it will go into the while-loop.
    • if your word is in the list it will remove the word from the list and add 1 to the value of the word in word_dict. Here it assumes that the word is already in the word_dict, but it isn't. So the code will give an error. No need to add a while-loop thus.