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Java Java Basics Perfecting the Prototype Looping until the value passes

Vahid Rezaei
Vahid Rezaei
1,823 Points
Posted by Vahid Rezaei
Vahid Rezaei
1,823 Points

I need to understand the error reason and find a solution for this , tnx

is this coding with error sysntax

Example.java 
// I have initialized a java.io.Console for you. It is in a variable named console.
do {
  String response = console.readLine("Do you understand do while loops");
  if (response.equalsIgnoreCase("no")) {
  console.printf("you are not allowed to go on.  try again.");
   } 
  }   while(response.equalsIgnoreCase("no"));

1 Answer

Ted Dunn
Ted Dunn
43,783 Points
Ted Dunn
Ted Dunn
43,783 Points

You need to declare the variable named response outside of the do while loop. Currently, the scope for the response variable is limited to be inside of the do while loop, but the condition for the while check is outside of the the loop, therefore, the variable you used inside the while condition check is undefined.

String response = "";

do {
    response = console.readLine("Do you understand do while loops?");
} while (response.equalsIgnoreCase("no"));