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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Antoine Solomon
Antoine Solomon
2,850 Points
Posted by Antoine Solomon
Antoine Solomon
2,850 Points

I seem to have an issue with my implmeentation of wordcount.py. Could someone take a look ?

Here's the details of the code I created for wordcount.py Now I ran this in the workspace and my local terminal and it looks correct. Just don't know why i get bummer message.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(sentence):
    seen = {} # the words that we have seen and the occurance of the words
    lower_case_sentence = sentence.lower()
    for word in lower_case_sentence.split(" "):
        if word in seen:
            seen[word] += 1
        else:
            seen[word] = 1
    return seen

1 Answer

Eric M
Eric M
11,546 Points
Eric M
Eric M
11,546 Points

You're very close but only splitting on spaces and likely only including spaces in your test cases in your local terminal. The Treehouse test cases will test on non-space whitespace as well (the bummer message should say "make sure you're splitting on all whitespace" but the impact of that is easy to overlook).

If you don't provide split() with any arguments it will split on all whitespace by default.

Antoine Solomon
Antoine Solomon
2,850 Points
Antoine Solomon
Antoine Solomon
2,850 Points

Thank you. I can't believe I missed that one.