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I still don't get why this isn't working
Please help I so comfused
def squared(num): if num == int: return int(num) ** 2 else: return(num * num) except ValueError: return(num) * len(num)
Bryan Reed11,747 Points
Instead of using an If and Else just use Try and Except. Part of why what you have isn't working is because you're using an Except without a Try
def squared(num): try: return int(num) ** 2 # OR int(num) * int(num). Either will give the SAME answer he's just giving you a choice # if the above return throws a ValueError because the num can't be converted into an integer except ValueError: return(num) * len(num) # then this except will run instead
Try and forget about using int(num) ** 2 or num * num because both of these operations will return the same answer