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Hossam Aly
1,986 PointsI stuck on code challenge-Array sort method
Hi guys I'm stuck on task number 2 can't figure out the right format for the function to list the Array in length order using the "length" property http://teamtreehouse.com/library/websites/javascript-foundations/arrays/methods-part-2-4 need help.
2 Answers
Paul Casey
Courses Plus Student 3,033 PointsThis MDN page for the sort() method gives a good description and framework for the function. It definitely helped me out. Just read the top part of the description and base your function on the 'compare' function shown.
So, in this example, your function just needs to be placed within the parentheses of the sort() method, and must tell the method to sort by each array item's .length property. The first part of your conditional could be:
saying2.sort(function(a,b){if (a.length < b.length) {
return -1; }});
With this, if a is shorter than b, it will be placed before b. Two more conditions should be added to handle when a is longer than b, and when they are the same length.
Hope this helps!!

Gary Mann
8,639 PointsHi Hossam, I'm going to get wordy in this reply for my own benefit. I'm trying to wrap my brain around JavaScript, too. And if I can explain this, it'll help me understand it.
So if we just said
saying2.sort()
the little man-in-the-machine wouldn't know how we want the values in our saying2 array sorted. We want them sorted by length. So we have to give it a function that compares the strings in our array and sorts them by length.
From the pop-up in the video @ 3:36: myArray.sort ( compareFunction ) sorts an array by using the compareFunction to determine the order.
The function we're going to give it will be
function ( a, b ) {
return a.length - b.length;
}
What will this function do? 'a' & 'b' are just variables within this anonymous function. We could've called them anything we want. If given values for these variables 'a' & 'b', it'll compare the length of 'a' to the length of 'b' by subtracting b.length from a.length .
So what, right?
Well when we put it altogether into our request to sort our saying2 array:
saying2.sort (
function ( a , b ) {
return a.length - b.length
}
);
it knows that we're using this function as a means to compare each value in saying2 and sort saying2 . Voila!
Taking two values from saying2 at a time, and plugging them in for 'a' & 'b', it'll compare them and return a.length - b.length . If a negative number is returned, 'a' must come before 'b' in our newly sorted saying2 array. If the function returns a positive number, then 'a' comes after 'b'. And if zero is returned, then they could go in either order.
I hope this is at least a little clear and not even more confusing.

Hossam Aly
1,986 PointsHi Gary That was very good answer Thank you so much for help
Gary Mann
8,639 PointsGary Mann
8,639 PointsThanks Paul!!
Your definition and link helped me wrap my brain around it even better. Seeing it written out as "if... if..." helps me grasp the short-hand used in the video.
Paul Casey
Courses Plus Student 3,033 PointsPaul Casey
Courses Plus Student 3,033 PointsGlad it helped! Mozilla Developer Network is an amazing resource and the explanations are always extremely helpful.
I haven't watched the video yet myself. I just discovered Treehouse today and am looking to brush up on my javascript and move forward from there!
Hossam Aly
1,986 PointsHossam Aly
1,986 PointsThanks Paul Welcome to treehouse And good luck