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Python SQLAlchemy Basics Introduction to SQLAlchemy Querying the Movie Database

I think I'm stuck again... SQLAlchemy Basics Challenge Task 2 of 2 Querying the Movie Database

Today, the theater is updating the list of movies on the sign outside. Create a variable named all_movies. It should hold all of the movies in the database in alphabetical order.

models.py
from sqlalchemy import create_engine, Column, Integer, String
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker


engine = create_engine(β€˜sqlite:///movies.db’, echo=False)
Session = sessionmaker(bind=engine)
session = Session()
Base = declarative_base()


class Movie(Base):
    __tablename__ = β€˜movies’

    id = Column(Integer, primary_key=True)
    movie_title = Column(String)
    genre = Column(String)

romance_movies = session.query(Movie).filter_by(genre='Romance').first()
for all_movies in session.query(Movie.all_movies).order_by(Movie.all_movies):
    print(all_movies.movie_title)

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points

Hey Trenton Spears, you are almost there.

Task 2 asks to create the variable all_movies only, no loop or printing required

  • the query is based on Movie as in query(Movie)
  • the order_by needs the correct attribute reference, as in order_by(Movie.movie_title)
  • need to include .all()

Post back if you need more help. Good luck!!!

Got it! Thank you sir!

all_movies = session.query(Movie).order_by(Movie.movie_title).all()