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Brendan Whiting
Front End Web Development Techdegree Graduate 84,735 PointsI think my answer could be better
Challenge accepted my code but I have a feeling it's less that ideal. Is there a better way to iterate through my list?
def string_factory(list, string):
string_list = []
for idx in range(len(list)):
string_list.append(string.format(**list[idx]))
return string_list
dicts = [
{'name': 'Michelangelo',
'food': 'PIZZA'},
{'name': 'Garfield',
'food': 'lasanga'},
{'name': 'Walter',
'food': 'pancakes'},
{'name': 'Galactus',
'food': 'worlds'}
]
string = "Hi, I'm {name} and I love to eat {food}!"
2 Answers
William Li
Courses Plus Student 26,868 PointsHi there,
Your solution is okay, but you could simplify it a bit by not using the range() function. Like such
def string_factory(ls, string):
string_list = []
for i in ls:
string_list.append(string.format(**i))
return string_list
I believe that makes the code cleaner and easier to read. Cheers.
Andreas cormack
Python Web Development Techdegree Graduate 33,011 PointsHi
another way of doing it.
def string_factory(myList,myString):
new_list = []
for dict in myList:
new_list.append(myString.format(**dict))
return new_list
Brendan Whiting
Front End Web Development Techdegree Graduate 84,735 PointsBrendan Whiting
Front End Web Development Techdegree Graduate 84,735 PointsThanks!