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Android Build an Interactive Story App (Retired) Finishing the User Interface Using a Model in the Controller

Posted by Shiv Anant Yadav
Shiv Anant Yadav
1,064 Points

I thought I did attach the code. Sorry. Where and how am I supposed to pass the string?

Please help ASAP

Kevin Faust
Kevin Faust
15,353 Points
Kevin Faust
Kevin Faust
15,353 Points

can you please post your code

Shiv Anant Yadav
Shiv Anant Yadav
1,064 Points

import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.EditText;

public class LandingActivity extends Activity {

public Button mThrustButton;
public TextView mTypeLabel;
public EditText mPassengersField;

public Spaceship mSpaceship;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_landing);

    mThrustButton = (Button)findViewById(R.id.thrustButton);
    mTypeLabel = (TextView)findViewById(R.id.typeTextView);
    mPassengersField = (EditText)findViewById(R.id.passengersEditText);

    // Add your code here!
}

}

Shiv Anant Yadav
Shiv Anant Yadav
1,064 Points

The LandingActivity interacts with the Spaceship model object we created. Start by setting mSpaceship to a new Spaceship object in the onCreate() method. Use the custom constructor that takes a String parameter, and pass in "FIREFLY" as the parameter.

This is the question

Shiv Anant Yadav
Shiv Anant Yadav
1,064 Points

Thanks Kevin.

1 Answer

Kevin Faust
Kevin Faust
15,353 Points
Kevin Faust
Kevin Faust
15,353 Points

All you do is add this right below where it says // Add your code here!:

 mSpaceship = new Spaceship("FIREFLY");

We are simply creating a new Spaceship object and passing it a string as a paramter. As written in the instructions, we pass in "FIREFLY" as a paramater