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Databases

Posted by Ailun Shen
Ailun Shen
4,874 Points

I tried LIKE '[a-k]%' I tried where Name >= 'A' and Name <= 'K' I give up

BS

3 Answers

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Since you didn't provide a link to the course page or reproduce the instructions I'm not sure what your intention is, but "<= 'K'" might not be what you want unless you want to include the letter "K" but nothing that begins with "K". If you want to include everything from A-K you would have better luck with "< 'L'" instead.

If that's not it, show your complete query and provide a link to the course page.

Ailun Shen
Ailun Shen
4,874 Points

https://teamtreehouse.com/library/querying-relational-databases/set-operations/set-operations

second question where they ask list every fruit vegetable A-K

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

I confirmed that my previous suggestion works in the challenge. Remember to apply the filter to both tables.

Ailun Shen
Ailun Shen
4,874 Points

Here's the problem There are two tables Fruit and Vegetable table. The Fruit table has a FruitID and a Name column and the Vegetable table has a VegetableID and Name column. Create a list of all fruits and vegetables starting with the letters A through K . In other words all fruit and vegetables that don't start with the letter L to Z.

i tried this...

SELECT Name from fruit WHERE Name >= 'A' AND Name <= 'K'
UNION
SELECT name from vegetable WHERE Name >= 'A' AND Name <= 'K'

but got this

Bummer! Your UNION queries didn't bring back a union of fruits and veggies beginning with the letters A through K!

I'm giving up

Ailun Shen
Ailun Shen
4,874 Points
Ailun Shen
Ailun Shen
4,874 Points

https://teamtreehouse.com/library/querying-relational-databases/set-operations/set-operations Link to it

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

As I said already, my original suggestion ("Name < 'L'") works in the challenge.

John Tester
John Tester
3,366 Points
John Tester
John Tester
3,366 Points

Agree with Steven, confirmed this works correctly where adding the where clause in both statements.