Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Perfecting the Prototype Looping until the value passes

Posted by Bernice Utsalo
Bernice Utsalo
305 Points

I used console.printf to print out the formatted string and it still says bummer

I want to know what to say

Example.java 
// I have initialized a java.io.Console for you. It is in a variable named console.
response = console.readLine("Do you understand do while loops?");
boolean isInvalidWord;
do { 
    response = console.readLine("Do you understand do while loops?");
    isInvalidWord = (response.equalsIgnoreCase("No"));
} while (isInvalidWord);
console.printf("Because you said <response>, you passed the test!");

1 Answer

John Johnson
John Johnson
11,790 Points
John Johnson
John Johnson
11,790 Points

printf uses %s for string formatting. Instead of placing <response> directly into the string, type %s where you want your variable to go, then place your variable after the string separated by a comma.

// I have initialized a java.io.Console for you. It is in a variable named console.

String response = console.readLine("Do you understand do while loops?");
do {
  response = console.readLine("Do you understand do while loops?");
} while ( response == "No" );

console.printf("Because you said %s you passed the test!", response);