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Java Java Basics Perfecting the Prototype Looping until the value passes

Posted by Bernice Utsalo
Bernice Utsalo
305 Points

I used console.printf to print out the formatted string and it still says bummer

I want to know what to say

Example.java 
// I have initialized a java.io.Console for you. It is in a variable named console.
response = console.readLine("Do you understand do while loops?");
boolean isInvalidWord;
do { 
    response = console.readLine("Do you understand do while loops?");
    isInvalidWord = (response.equalsIgnoreCase("No"));
} while (isInvalidWord);
console.printf("Because you said <response>, you passed the test!");

1 Answer

John Johnson
John Johnson
11,789 Points
John Johnson
John Johnson
11,789 Points

printf uses %s for string formatting. Instead of placing <response> directly into the string, type %s where you want your variable to go, then place your variable after the string separated by a comma.

// I have initialized a java.io.Console for you. It is in a variable named console.

String response = console.readLine("Do you understand do while loops?");
do {
  response = console.readLine("Do you understand do while loops?");
} while ( response == "No" );

console.printf("Because you said %s you passed the test!", response);