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Mark Bekhet
900 PointsI want some help for this challenge
Ok, so for this challenge I try to make a mix between to iterables. I tried many things but this code is the most logical for me to output something like the example. The problem now is when I try this code on my computer it appears that the index is out of range. I don't know the reason for this error. The code appears logical to me.
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
def combo(nums,strings):
new_list= []
index = 0
for num in nums:
for string in strings:
if string[index] == string:
new_list.append((num,string))
index = index + 1
return new_list
2 Answers
Dave StSomeWhere
19,870 PointsYes your code is logical but as the error says index is out of range
if string[index] == string:
What is the valid index range for string?
Mark Bekhet
900 PointsCan you be more explicit please. In the line of code which you copied, i want a statement which is always true but i don't know the length of the string itself
Dave StSomeWhere
19,870 PointsSince you do
for string in strings:
you are iterating through strings - string is a single character it can only ever be index 0 (easy to get out of range). What variable should be used with index? Does that help?
Mark Bekhet
900 PointsI saw my mistake after i posted the comment the mistake is that i forgot an s to string[index]