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# I was playing in the REPL with this function and can't figure out why word2 returns an empty string after join method?

Basically as I stated. In the REPL word1 joins into 'str' just like i was hoping, but word2 returns "". If it's the same logic what is causing this?

sillycase.py
```def sillycase(string):
string = list(string)
half = int(len(string)) // 2
word1 = string[:half]
word1 = "".join(word1[:half]).lower()
word2 = string[half:]
word2 = "".join(word2[half:]).upper()
return word1 + word2
```

You don't need the join, but what's happening here would be the same with or without it.

When "word2" is first assigned, it gets "half" of the iterable: "`word2 = string[half:]`"

Then, on the next line, the "join" starts with taking another slice: "`word2[half:]`"

But if the first slice made it only "half" long, then another slice that has a start value of "half" would not have any content.

HA that makes total sense now! I updated the code to:

word1 = "".join(word1).lower()

and

word 2 = "".join(word2).upper()

Now its perfect. Thank you for helping me understand why it had no content.

I don't kwow why you should use "join". You can do this:

```def sillycase(string):
half = int(len(string)) // 2
word1 = string[:half].lower()
word2 = string[half:].upper()
return word1 + word2
```

I was originally using concepts taught in the video.

Basically I was using join because I turned string into a list and had to turn it back.

Your code is how I passed the challenge, I was just trying to understand why word 2 returned and empty string with the same logic.