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Start your free trialPayton Roedel
1,555 PointsI was playing in the REPL with this function and can't figure out why word2 returns an empty string after join method?
Basically as I stated. In the REPL word1 joins into 'str' just like i was hoping, but word2 returns "". If it's the same logic what is causing this?
def sillycase(string):
string = list(string)
half = int(len(string)) // 2
word1 = string[:half]
word1 = "".join(word1[:half]).lower()
word2 = string[half:]
word2 = "".join(word2[half:]).upper()
return word1 + word2
2 Answers
Steven Parker
231,269 PointsYou don't need the join, but what's happening here would be the same with or without it.
When "word2" is first assigned, it gets "half" of the iterable: "word2 = string[half:]
"
Then, on the next line, the "join" starts with taking another slice: "word2[half:]
"
But if the first slice made it only "half" long, then another slice that has a start value of "half" would not have any content.
Kars Jansens
5,348 PointsI don't kwow why you should use "join". You can do this:
def sillycase(string):
half = int(len(string)) // 2
word1 = string[:half].lower()
word2 = string[half:].upper()
return word1 + word2
Payton Roedel
1,555 PointsI was originally using concepts taught in the video.
Basically I was using join because I turned string into a list and had to turn it back.
Your code is how I passed the challenge, I was just trying to understand why word 2 returned and empty string with the same logic.
Payton Roedel
1,555 PointsPayton Roedel
1,555 PointsHA that makes total sense now! I updated the code to:
word1 = "".join(word1).lower()
and
word 2 = "".join(word2).upper()
Now its perfect. Thank you for helping me understand why it had no content.