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iOS Swift 2.0 Collections and Control Flow Control Flow With Conditional Statements FizzBuzz

Anuradha Nath
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.a{fill-rule:evenodd;}techdegree
Anuradha Nath
iOS Development Techdegree Student 2,686 Points
Posted by Anuradha Nath
.a{fill-rule:evenodd;}techdegree
Anuradha Nath
iOS Development Techdegree Student 2,686 Points

I was writing the fizzbuzz code in the editor and I am getting following error in the treehouse editor.Please help:

code entered by me are between the comment markers: func fizzBuzz(n: Int) -> String { // Enter your code between the two comment markers if ( n%3 == 0){ return "Fizz" } else if (n%5 == 0){ return "Buzz" } else if (n%3==0 && n%5==0){ return "FizzBuzz" } else { // End code return "(n)" } }

getting following error: Double check your logic for FizzBuzz values and make sure you're returning the correct string!

Not compilation error but can't submit my answer. I tried both switch and If cases.

Thanks, Anuradha.

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
  if ( n%3 == 0){
      return "Fizz"
  }  else if (n%5 == 0){
      return "Buzz"
  }  else if (n%3==0 && n%5==0){
      return "FizzBuzz"
  } else { 
   // End code
  return "\(n)"
  }
}
Anuradha Nath
seal-mask
.a{fill-rule:evenodd;}techdegree
Anuradha Nath
iOS Development Techdegree Student 2,686 Points
Anuradha Nath
.a{fill-rule:evenodd;}techdegree
Anuradha Nath
iOS Development Techdegree Student 2,686 Points

I got it, I had to arrange my conditions to match the requirement. the above written code is logically incorrect, it will never satisfy elseif condition.

Thanks, Anuradha.

1 Answer

Alexander Davison
Alexander Davison
65,469 Points

You did a good job! The bug here is very sneaky and very cleverly hid. Let's say our number that we're going to check is 15. 15 Is divisible by both 3 and 5, so it should return "FizzBuzz". But if you tried your code, it will return "Fizz". Here's why: When you run your function/method, it checks if 15 is divisible by 3 first. Since it is divisible by 3, it passes and it returns just "Fizz". So you should check if the number is divisible by 3 and 5 first. If you fix your code it should look like this:

func fizzBuzz(n: Int) -> String {
    // Enter your code between the two comment markers
    if (n % 3 == 0 && n % 5 == 0){
        return "FizzBuzz"
    } else if (n%5 == 0){
        return "Buzz"
    } else if (n % 3 == 0){ 
        return "Fizz"
    } else { 
        // End code
        return "\(n)"
    }
}

Good luck!

Hope this helps, Alex

Alexander Davison
Alexander Davison
65,469 Points

Oops I didn't see your little comment below your answer saying you already found the answer. LOL :)