Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialTinotenda Emmanuel Nyamukapa
5,127 Pointsi would some help
I'm trying to complete this challenge please help
import datetime
starter = datetime.datetime(2015, 10, 21, 16, 29)
# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.
## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)
def time_machine(intr, item):
if item == 'years':
new_item = days
else:
pass
new_time = starter - datetime.timedelta(new_item=(intr*365))
return new_time
2 Answers
Pratham Mishra
14,191 Points''def time_machine(time_int, years): if years == 'years': time_int = 365 years = 'days' return starter + datetime.timedelta(*{years : time_int})'''
Steven Parker
231,275 PointsHere are a few hints:
- the value multiplication (by 365) should only occur for "years"
- the timedelta should be added to the starter time
- the key=value syntax can only be used with a literal key name (you might consider a dictionary)
- an "else" is not needed if all it does is "pass"