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If argument can be turned into a int challenge, need help please
This is what i got so far, the error it is giving is just bummer try again, so im a little lost here?
# EXAMPLES # squared(5) would return 25 # squared("2") would return 4 # squared("tim") would return "timtimtim" def squared(string): try: if int(string): return squared(string) except ValueError: return(string * len(string))