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Start your free trialPhilip Kroupoderov
Front End Web Development Techdegree Graduate 21,641 PointsIf he wrote $("button").removeClass("selected"); then why does the each() method even exist?
I thought he would write the following and use each():
$(document).ready(function () {
$('button').click(function () {
$("button").each(function() {
$(this).removeClass("selected")
});
$(this).addClass("selected");
});
});
So can someone tell in which case should I use the each method and in which cases I can just call a method on a jQuery object which contains multiple elements?? And why does the each method exist in the first place when typing $("button").removeClass("selected"); will loop through all elements with the class of selected and remove the class from them??
1 Answer
Steven Parker
231,269 PointsTypically, if a method exists that performs the desired operation on all elements in a jQuery object, you would use that by itself and not use ".each".
You would use ".each" when you want to apply some code to every element for which there is no handy jQuery method that can do the job.