if (highNumber) question

It works in JavaScript the same as if (highNumber == true) if highNumber were a boolean, but it's not a boolean, so how does it work? I understand your confusion. The answer is that when not provided with a value to compare to, the conditional checks if it is "truthy" or "falsey" by deciding that some values are inherently true and some are inherently false. For example, when checking numbers, a zero ( 0 ) is considered false, whereas a 1 (or any other number) is considered true. This way of coding makes it easier and shorter to write code that accomplishes the same thing, without having to put in lots of checks for bad values. In reality, if (highNumber) {} is really more like: if (highNumber > 0 && highNumber != null && highNumber != NaN && highNumber != undefinded && highNumber != false){}. This is very useful when you might be checking against a value that might be undefined or evaluates to an error, like NaN (which is one thing that could happen in this challenge). I hope that helps.

Another thing I should mention is that I don't really like the alert message, as it tells the user to enter a number, but if you put in a zero, it will also fail the condition, so the message should really say "You need to provide a number greater than one"