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JavaScript jQuery Basics (2014) Creating a Simple Drawing Application Perform: Part 2

Yonatan Medan
Yonatan Medan
3,943 Points
Posted by Yonatan Medan
Yonatan Medan
3,943 Points

if i dont click on the color controls li the stroke is black why is it?

var $colorControls = $(".controls li");
var $newColorButton = $("#revealColorSelect");
var color = $("li .selected").css("backgroun-color");
var context = $("canvas")[0].getContext("2d");
var $canvas = $("canvas");
var lastEvent;
var mousedown =false;

//selecting a color will de select all the other color

$(".controls").on("click","li",function(){
  $(this).choose();
  color = $(this).css("background-color")
  console.log(color)
});
//clicking on new color will show the new color div

$newColorButton.click(function(){
  $("#colorSelect").toggle();
  changeColor();
  $("body").scrollTop(300);
});
// selecting color will show the color on the span


function changeColor (){
  var r = $("#red").val();
  var g = $("#green").val();
  var b = $("#blue").val();
  $("#newColor").css("background-color", "rgb(" +r +"," +g+","+b+")");
}
$("input[type = range]").change(changeColor);


$.fn.choose = function () {
    $(this).addClass("selected").siblings().removeClass("selected");
};

$(document).on("click","#addNewColor", function (){
  alert("hello");
  $(".controls ul").append($("<li></li>").css("background-color",$("#newColor").css("background-color")));
 $(".controls ul li:last").choose();
});


$canvas.mousedown(function(e){
  lastEvent = e;
  mousedown = true;
}).mousemove(function(e){
  if (mousedown){
context.beginPath();
context.moveTo(lastEvent.offsetX,lastEvent.offsetY);
context.lineTo(e.offsetX,e.offsetY);
context.strokeStyle = color;
context.stroke();
lastEvent = e;}
}).mouseup(function(){
mousedown = false
});
Bobby Verlaan
Bobby Verlaan
29,538 Points
Bobby Verlaan
Bobby Verlaan
29,538 Points

I didn't have the time to look at your question yet. But please post your code with markdown (see cheatsheet) in a readable format like below. In that way we can follow along pretty simple. Get back to it later this day if no one else found the solution yet ;-)

If you check your code you find there are missing some semicolons at some lines that should be there. Also check the closing of a function with the syntax of function(){};

var $colorControls = $(".controls li"); 
var $newColorButton = $("#revealColorSelect"); 
var color = $("li .selected").css("backgroun-color"); 
var context = $("canvas")[0].getContext("2d"); 
var $canvas = $("canvas"); 
var lastEvent; 
var mousedown =false;

//selecting a color will de select all the other color

$(".controls").on("click","li",function(){ 
  //clicking on new color will show the new color div
  $(this).choose(); 
  color = $(this).css("background-color") 
  console.log(color) 
}); 

$newColorButton.click(function(){ 
  $("#colorSelect").toggle(); changeColor(); 
  $("body").scrollTop(300); 
}); // selecting color will show the color on the span

function changeColor (){ 
  var r = $("#red").val(); 
  var g = $("#green").val(); 
  var b = $("#blue").val(); 
  $("#newColor").css("background-color", "rgb(" +r +"," +g+","+b+")"); 
} 

$("input[type = range]").change(changeColor);
$.fn.choose = function () { $(this).addClass("selected").siblings().removeClass("selected"); };
$(document).on("click","#addNewColor", function (){ 
  alert("hello"); 
  $(".controls ul").append(
    $("").css("background-color",
    $("#newColor").css("background-color"))); 
    $(".controls ul li:last").choose(); 
});

$canvas.mousedown(function(e){ 
  lastEvent = e; mousedown = true; 
}).mousemove(function(e){ 
  if (mousedown){ 
    context.beginPath(); 
    context.moveTo(lastEvent.offsetX,lastEvent.offsetY); 
    context.lineTo(e.offsetX,e.offsetY); 
    context.strokeStyle = color; 
    context.stroke(); 
    lastEvent = e;
  } 
}).mouseup(function(){ 
  mousedown = false 
});
Iain Simmons
Iain Simmons
Treehouse Moderator 32,305 Points

Hi Yonatan Medan, I've formatted your question with a code block. Please see the Markdown Cheatsheet (linked below the question/answer/comment text box) for instructions on how to format code blocks.

1 Answer

Iain Simmons
MOD
Iain Simmons
Treehouse Moderator 32,305 Points
Iain Simmons
Iain Simmons
Treehouse Moderator 32,305 Points

So you have a couple of typos when you set the initial value of the color variable:

var color = $("li .selected").css("backgroun-color");

Should be:

var color = $(".selected").css("background-color");