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# If Operator

For this challenge, we'd like to know in a range of values from 1 to 100, how many numbers are both odd, and a multiple of 7.

To start us off, I've written a for loop to iterate over the desired range of values and named the local constant n. Your job is to write an if statement inside the for loop to carry out the desired checks.

If the number is both an odd number and a multiple of 7, append the value to the results array provided.

Hint: To check for an odd number use the not operator to check for "not even"

operators.swift
```var results: [Int] = []

for n in 1...100 {
if n || even && multiplier * 7 {
print(results.append[Int] = [])
}
}
```

Devon,

Your not quite there. Try something like this:

```var results: [Int] = []

for n in 1...100 {

if (n % 7 == 0) && (n % 2 == 1) //checks that n is divisible by 7 AND is odd
{
results.append(n) //if n passes if logic, append it to the results array.
}

}
```

Thank you very much. I notice that as I continue along the code challenges adds on to what I've already learned previously. Also, it gets a bit more complicated. The comments at the end also help me to understand a little bit better as well. Thanks again.