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Java Java Basics Perfecting the Prototype String Equality

Rishabh Soni
Rishabh Soni
827 Points

if statement

add if statement that checks if the firstExample is equal ignoring case to thirdExample.If it is print out "first and third are the same ignoring case". String firstExample = "hello"; String secondExample = "hello"; String thirdExample = "HELLO"; if (firstExample.equalsIgnoreCase("HELLO")){ console.printf("first and third are the same ignoring case"); }

Equality.java
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if (firstExample.equalsIgnoreCase("HELLO")){
console.printf("first and third are the same ignoring case");
}

2 Answers

Instead of passing a value, pass a variable.

String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if (firstExample.equals(secondExample)){
    console.printf("first is equal to second");
}

if (firstExample.equalsIgnoreCase(thirdExample)){
    console.printf("first and third are the same ignoring case");
} 

[MOD - changed to answer; careful with giving out code solutions, though! - srh]

Gergely Horvath
PLUS
Gergely Horvath
Courses Plus Student 8,207 Points

You are not giving the thirdExample variable as an argument to the equalsIgnoreCase method, instead you are providing a string here:

firstExample.equalsIgnoreCase("HELLO")