If the filename contains the string "fun", display the name of the file surrounded by H3 tags.

Challenge Task 2 of 3

If the filename contains the string "fun", display the name of the file surrounded by H3 tags.

HINT: strpos will return 0 if the result is found at the beginning of the file. Returns FALSE if the needle was not found.

Allow me to preface this by stating that I am quite the noob when it comes to programming, so my question comes from lack of experience with the logic of PHP. My question is not asked because I'm stuck, but to better understand WHY the language works in the fashion it does. Below is the code:

<?php
//add code here

$files = scandir('example');

foreach ($files as $file) {
  if (strpos($file, 'fun') !== FALSE) {
    echo '<h3>' . $file . '</h3>';
  }
}

My question is, why inside of the if control structure, when looking as the string function strpos, does the argument work as !== FALSE, or IS NOT FALSE, but does not work as == TRUE? The code below does not work:

<?php
//add code here

$files = scandir('example');

foreach ($files as $file) {
  if (strpos($file, 'fun') == TRUE) {
    echo '<h3>' . $file . '</h3>';
  }
}

Logically, it would seem to me, that the comparison operator/boolean combination !== FALSE is the same as == TRUE, because 'is not false' means the same is 'is true'. I would think either could be used to return the same value when used inside of the function argument. Obviously this is not the case. I'm just wondering why.

I'm sure it has something to do with the way that strpos searches for the string and returns the Boolean, am I correct? From what I read in the PHP Manual, it would appear that strpos only returns a FALSE value, so it doesn't know what to do with a TRUE value, or evaluates everything matching the argument as FALSE, maybe?

Any explanation would be helpful. Thank you.