im cannot seem to correct this error...its saying the code took to long to run

Question

i do not know whether to keep the while True as it or change it according to something in the code challenge
```even.py
import random
start = 5
while True:
    def even_odd(num):
        num = random.randint(0, 99)
        if num % 2 == 0:
            print("{} is even".format(num))
        else:
            print("{} is odd".format(num))
        return not num % 2
    start -= 1
even_odd()   
```

Ken Alger · Accepted Answer

Nikhil;
Okay, let's back up a minute as it seems you're overall off track a bit, which is fine, this stuff isn't super intuitive.
At the end of Task 2 your code should, more or less, look like this, yes?
```python
import random
start = 5
def even_odd(num):
        return not num % 2
```
And here are the instructions for Task 3:
Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!
Let's take those steps one at a time.
Make a while loop that runs until start is falsey. Recall that a zero value meets the condition so we can either do while (start > 0): ... or we could simply do while start: ...
```python
import random
start = 5
def even_odd(num):
        return not num % 2
while start:
```
Next we have the code for our number generator and we can assign that to a variable name. num seems as good as any.
```python
import random
start = 5
def even_odd(num):
        return not num % 2
while start:
        num = random.randint(1, 99)
```
If our random number, num is even we want to print that it is. Same for an odd number. We are instructed to use our even_odd method to do so. So we don't need to change that method at all.
```python
import random
start = 5
def even_odd(num):
        return not num % 2
while start:
        num = random.randint(1, 99)
        if even_odd(num):
             // print our even output
        else:
            // print our odd output
```
Finally, we decrement start by 1. That should be doable.
```python
import random
start = 5
def even_odd(num):
        return not num % 2
while start:
        num = random.randint(1, 99)
        if even_odd(num):
             // print our even output
        else:
            // print our odd output
        start -=1
```
That should do it from a logic standpoint. I'll leave it to you to complete the print statements. ;-)
Post back if you're still stuck, Nikhil. Great job sticking with this as well. You got this!
Ken

Nikhil Alexander · Answer

```python
import random
start = 5
while (start > 0):
    def even_odd(num):
        num = random.randint(1, 99)
        if num % 2 == 0:
            print("{} is even".format(num))
        else:
            print("{} is odd".format(num))
        return not num % 2
    start -= 1
even_odd()

I even tried using
python
while (int(start) > 0):

Ken Alger · Answer

Nikhil;
Actually, the way the above code is written, the loop will never end. You would need to check the value of start to achieve the results you want. Something along the lines of:
```python
start = 5
while (start > 0):
    ...
    start -= 1
```
Doing while True: runs forever unless there is a break statement.
Ken

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Nikhil Alexander

Nikhil Alexander

im cannot seem to correct this error...its saying the code took to long to run

Ken Alger

Ken Alger

Nikhil Alexander

Nikhil Alexander

3 Answers

Ken Alger

Ken Alger

Nikhil Alexander

Nikhil Alexander

Ken Alger

Ken Alger

Nikhil Alexander

Nikhil Alexander

Ken Alger

Ken Alger

Nikhil Alexander

Nikhil Alexander

Ken Alger

Ken Alger

Nikhil Alexander

Nikhil Alexander