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Python Python Basics (2015) Number Game App Squared

Posted by Trenton Cain
Trenton Cain
550 Points

I'm completely lost. I need assistance with finishing my code

import math

def squared(num): try: num ** 2 except TypeError: num * int(num) else: if num % 2 == 0: return num ** 2

squared.py 
import math

def squared(num):
    try:
        num ** 2 
    except TypeError:
        num * int(num)
    else:
        if num % 2 == 0:
            return num ** 2

2 Answers

Andrey Misikhin
Andrey Misikhin
16,529 Points
Andrey Misikhin
Andrey Misikhin
16,529 Points

You must save results in variables and use ValueError.

import math

def squared(num):
    try:
        num = int(num) ** 2 
    except ValueError:
        num *= len(num)
    return num
Steven Parker
Steven Parker
229,670 Points
Steven Parker
Steven Parker
229,670 Points

A few hints:

  • the "int" conversion must be done inside the "try" block for it to detect exceptions
  • the type of exception you will be looking for is "ValueError"
  • you won't need an "if" test
  • when the conversion fails, you need to multiply the argument by its length