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Damjan Bozinovski
9,916 PointsI'm doing exactly the same as Dave, still doesn't run properly.
function getRandomNumber( lower, upper ) { if (isNaN(lower) || isNaN(upper)){ throw new Error('Mistake!'); } return Math.floor(Math.random() * (upper - lower + 1)) + lower; }
console.log( getRandomNumber( 'nine', 24 ) ); console.log( getRandomNumber( 1, 100 ) ); console.log( getRandomNumber( 200, 'five hundred' ) ); console.log( getRandomNumber( 1000, 20000 ) ); console.log( getRandomNumber( 50, 100 ) );
2 Answers
Clayton Perszyk
Treehouse Moderator 48,723 PointsHey Damjan,
Your code is working fine. The reason it is not logging all calls to getRandomNumber is that the first call throws the Error you set up in the if clause, stopping the code from continuing to run; so the remaining calls to getRandomNumber never get called.
Eshaa Dhall
Full Stack JavaScript Techdegree Student 13,122 PointsThe same is happening with my code, I'm using the prompt to enter the value, i even pasred the prompt value to INT but it still gets stuck at the if clause of the function getRandom.
function getRandom(high, bottom){ if(isNaN(high) || isNaN(bottom)) { throw new Error('enter a number.'); }
return Math.floor(Math.random() * (high - bottom + 1)) + bottom;
}
var top=prompt('Enter the High Value'); var low=prompt('enter the bottom value'); var top1=parseInt(top); var low1=parseInt(low); var random_number=getRandom(top1,low1); alert(random_number);
Leo Marco Corpuz
18,975 PointsLeo Marco Corpuz
18,975 PointsI checked my code over and over and nothing shows up in the console.
function getRandomNumber(lower,upper) { if(isNaN(lower)||isNaN(upper)){ throw new Error('Sorry, please enter a number.'); } return Math.floor(Math.random() * (upper - lower + 1)) + lower;
}
console.log( getRandomNumber( 'nine', 24 ) ); console.log( getRandomNumber( 1, 100 ) ); console.log( getRandomNumber( 200, 'five hundred' ) ); console.log( getRandomNumber( 1000, 20000 ) ); console.log( getRandomNumber( 50, 100 ) );