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PHP Build a Simple PHP Application Adding a Contact Form Concatentation

Chris Andruszko
Chris Andruszko
18,392 Points
Posted by Chris Andruszko
Chris Andruszko
18,392 Points

I'm either too tired for this, or there's a glitch...

I'm stuck on this challenge (Task 2 of 4): "Create a variable called fullName and assign it a value equal to the concatenation of the firstName variable, a space, the middleName variable, a space, and the lastName variable." https://teamtreehouse.com/library/build-a-simple-php-application/adding-a-contact-form/concatentation

This code doesn't work:

$fullName = $firstName . " " . $middleName . " " . $lastName;
$firstName = "Mike";
$middleName = "the";
$lastName = "Frog";

This code doesn't work:

$fullName = "$firstName $middleName $lastName";
$firstName = "Mike";
$middleName = "the";
$lastName = "Frog";

This code doesn't work (spaces in the variables themselves):

$fullName = $firstName . $middleName . $lastName;
$firstName = "Mike ";
$middleName = "the ";
$lastName = "Frog";

What am I doing wrong?

Michael Makali'i Fernandez
Michael Makali'i Fernandez
8,090 Points

edit: added comment as an answer.

Chris Andruszko
Chris Andruszko
18,392 Points
Chris Andruszko
Chris Andruszko
18,392 Points

Thanks, Michael! That was it. Sure enough, I was just being stupid.

I tried to rate and reply to your comment, but for some reason those options aren't available to me. Something I'll contact support about.

But thanks for you help!

1 Answer

Michael Makali'i Fernandez
Michael Makali'i Fernandez
8,090 Points

<?php

$firstName = "Mike";

$middleName = "the";

$lastName = "Frog";

$fullName = $firstName . " " . $middleName . " " . $lastName;

echo "The designer at Shirts 4 Mike shirts is named ____";

?>

Not The problem looks like you are using variables before they are declared and initialized. If you place fullName after the declared and initialized variables, it will work.