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JavaScript JavaScript Loops, Arrays and Objects Tracking Multiple Items with Arrays Iterating through an Array

Erin Agobert
Erin Agobert
4,781 Points
Posted by Erin Agobert
Erin Agobert
4,781 Points

I'm getting the error that I should log the numbers in order. The JS console shows all numbers are in order. Pls Help.

I thought I understood this lesson, but now I'm thoroughly confused.

script.js 
var temperatures = [100,90,99,80,70,65,30,10];

var tempList="<ol>";

for ( var i = 0; i < temperatures.length; i += 1) {
 tempList += "<li>" + temperatures[i] + "</li>";
}
tempList += "</ol>";
console.log(temperatures);
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
Tim Renner
Tim Renner
11,163 Points

Good job! You did what was asked, and then some. The challenge isn't looking for the <ol><li> tags wrapped around it. So you can simplify it to console.log(temperatures[i]) and put it inside the for...loop so it runs once for every array item. Wrapping with HTML is good for presentation, while logging to the console is plain text.

Erin Agobert
Erin Agobert
4,781 Points
Erin Agobert
Erin Agobert
4,781 Points

Thank you Tim and Steven! I thought I tried both ways, but I'm pretty sure I missed something. I tried the challenge 2 ways....

//Simplified as suggested and moving the console.log "inside" the loop.//

var temperatures = [100,90,99,80,70,65,30,10];

for ( var i = 0; i < temperatures.length; i += 1) { console.log(temperatures[i]); }

//AND keeping the ordered list and moving the console.log "inside" the loop.//

var temperatures = [100,90,99,80,70,65,30,10];

var tempList="<ol>";

for ( var i = 0; i < temperatures.length; i += 1) { tempList += "<li>" + temperatures[i] + "</li>"; tempList += "</ol>"; console.log(temperatures[i]); }

1 Answer

Steven Parker
Steven Parker
229,644 Points
Steven Parker
Steven Parker
229,644 Points

The challenge instructions say, "Inside the loop, log the current array value to the console", but the code here is building a string in side the loop and logging it after the loop.

Also, as Tim suggested, you would not use HTML tags when logging to the console. They do not perform the same job in the log as they do on the page.