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Start your free trial###### Daniel Bourke

3,870 Points# I'm having trouble understanding what exactly this question is asking.

Hey guys,

I'm stuck on this challenge mostly because I'm having trouble understanding the code/question.

The example shows a move function that takes in two arguments.

I'm having trouble with the first argument, the x, y, "hp"? How does it manage to go from (0, 1, 10) to (0, 9, 5)?

I understand it loses hp, but I can't conceptualise the transition from 1 to 9, unless it moves through the wall?

If anyone could explain the question in a different way, that would be greatly appreciated!

Thank you.

```
# EXAMPLES:
# move((1, 1, 10), (-1, 0)) => (0, 1, 10)
# move((0, 1, 10), (-1, 0)) => (0, 1, 5)
# move((0, 9, 5), (0, 1)) => (0, 9, 0)
def move(player, direction):
x, y, hp = player
return x, y, hp
```

## 1 Answer

###### Brendan Whiting

**Front End Web Development**Techdegree Graduate 84,731 Points

These 3 test cases are independent. The output of the 1st case happens to be in input of the 2nd, but the 3rd case is not related at all. Let’s break down the 3 test cases:

```
# move((1, 1, 10), (-1, 0)) => (0, 1, 10)
```

Player’s x position is 1, he’s asking to move -1 in the x direction. That’s allowed so now his x position is 0, and his hit points are the same.

```
# move((0, 1, 10), (-1, 0)) => (0, 1, 5)
```

Player’s x position is 0, he’s asking to move -1 in the x direction. That’s not allowed so 5 points are subtracted from his hit points and his x position is still 0.

```
# move((0, 9, 5), (0, 1)) => (0, 9, 0)
```

Player’s y position is 9, he’s asking to move 1 in the y direction. That’s not allowed so 5 points are subtracted from his hit points and his y position is still 9.

## Daniel Bourke

3,870 Points## Daniel Bourke

3,870 PointsThanks, Brendan!

That was confusing me. I managed to solve it in the end.