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iOS Swift 2.0 Collections and Control Flow Control Flow With Conditional Statements FizzBuzz

Thomas McNish
Thomas McNish
10,893 Points
Posted by Thomas McNish
Thomas McNish
10,893 Points

I'm not getting any errors from the compiler, so I'm not sure why my code isn't working.

Here's my code. It worked in Xcode, but I'm not getting it in the Treehouse compiler. What am I doing wrong?

if (n % 3 == 0) {
    return("Fizz")
} else if (n % 5 == 0) {
    return("Buzz")
} else if (n % 3 == 0 && n % 5 == 0) {
    return("FizzBuzz")
}
fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
  if (n % 3 == 0) {
    print("Fizz")
} else if (n % 5 == 0) {
    print("Buzz")
} else if (n % 3 == 0 && n % 5 == 0) {
    print("FizzBuzz")
} 
  // End code
  return "\(n)"
}

1 Answer

Caleb Kleveter
MOD
Caleb Kleveter
Treehouse Moderator 37,862 Points
Caleb Kleveter
Caleb Kleveter
Treehouse Moderator 37,862 Points

This is a rather interesting bug that you have.

The way an if-statement works is the first case is checked. Is it true? If yes, execute the code for that case, then exit the if block. If no, then continue the process through the rest of the cases.

What is happening to you is the number is divisible by 3 or 5, that following code is executed, and it exits the if-statement. The last statement is never reached!

So have this case:

(n % 3 == 0 && n % 5 == 0)

At the top. Problem solved!

Thomas McNish
Thomas McNish
10,893 Points
Thomas McNish
Thomas McNish
10,893 Points

Ha! That's it! Thank you so much. I knew it had to be logical because there were no compiler errors, but I don't think I would've caught that oversight in a million years, so...thanks for saving me a millions years!