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arun takkar
454 PointsI'm not getting the instructions right please Help
I'm solving according to instructions but no luck till now , Please Help
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^/$', views.ArticleList.as_view(), name="list"),
url(r'^(?P<pk>\d+)/$', views.ArticleDetail.as_view(), name="detail")
]
from django.views.generic import ListView, DetailView
from . import models
class ArticleList(ListView):
model = models.Article
class ArticleDetail(DetailView):
model = models.Article
<h1>Articles</h1>
<ul>
{% for title in article_list %}
<li>{{ title }}</li>
{% endfor %}
</ul>
<h1>{{ title }}</h1>
<p>{{ author }}</p>
<body>
{{ author }}|linebreaks
</body>
1 Answer
Tatiana Vasilevskaya
Python Web Development Techdegree Graduate 28,600 PointsArticleList view passes article_list variable, holding all the articles, to the article_list.html context. You have to print a list of all article titles.
<h1>Articles</h1>
<ul>
{% for article in article_list %}
<li>{{ article.title }}</li>
{% endfor %}
</ul>
ArticleDetail view passes an article variable to the article_detail.html context. And you have to print all the article details - title, author and body. Also, when you apply a linebreaks filter it should go inside curly braces.
<h1>{{ article.title }}</h1>
<p>{{ article.author }}</p>
<body>
{{ article.body|linebreaks }}
</body>