Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Clifford Gagliardo
Courses Plus Student 15,069 PointsI'm not sure what's going on here.
I am having a hard time breaking down the problem and figuring out which solutions to use for them. Any pointers or advice would be appreciated.
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
teachers={"cliff":["music", "photography", "writing"], "fulmer":["band","theory"], "cindy":["trumpet","horn"]}
def num_teachers(teachers):
return len(teachers.keys())
def num_courses(teachers):
courses=0
for i in teachers:
courses+=len(teachers[i])
return courses
def courses(teachers):
course_list=[]
for i in teachers.values():
course_list+=i
return course_list
def most_courses(teachers):
max_count=0
most=""
for i in teachers.values():
max_count+=1
1 Answer

Steven Parker
215,972 PointsIn your loop, you will probably want to check if the count of courses in the current item is greater than the max_count. If it is, you would copy that count into max_count and also store that teacher's name in most. After the loop has finished you can return most.