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Python Python Basics (2015) Shopping List App Continue

Posted by Yaumel Betancourt
Yaumel Betancourt
Courses Plus Student 7,119 Points

I'm not understanding the question. I thought it was asking to skip any element on the list that has a value of "a".

breaks.py 
def loopy(items):
    for item in items:
      if item == 'a':
        continue
      print(item)

2 Answers

jrabello
jrabello
17,917 Points
jrabello
jrabello
17,917 Points

hey Yaumel, your code is almost right, you're only missing the index part, you need 2 check if 'a' is at index 0 of item

Yaumel Betancourt
Yaumel Betancourt
Courses Plus Student 7,119 Points

Ok, I rewrote the code and tried it out on the terminal and it worked(printed out all of the items with the exception of the first one if it was "a"). However, I'm still getting it wrong on the challenge.

def loopy(items):
    for item in items:
      if items.index(item) == 0 and item == 'a':
        continue
      else:
        print(item)
jrabello
jrabello
17,917 Points
jrabello
jrabello
17,917 Points

to check the first element of item we use indexing -> item[0] :)