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Python Django REST Framework RESTful Django Create a ListView with a POST

I'm stuck..

OK, now you need to update the list view to handle creating a new Game instance. I've renamed the view for you, and updated the URL, but I want you to create the post method.

post takes the same arguments as get. You'll want to create a serializer instance from the request's data attribute. Then, if it's valid, save it and return the data as a Response.

If it's not valid, be sure to raise an exception. I think there's an argument for doing that automatically. Do you remember what it was?

Be sure that your response has a 201 status code.

scorekeeper/views.py
from rest_framework.response import Response
from rest_framework.views import APIView

from . import models
from . import serializers


class GameListCreate(APIView):
    def get(self, request, format=None):
        games = models.Game.objects.all()
        serializer = serializers.GameSerializer(games, many=True)
        return Response(serializer.data)

    def post(self,request,format=None):
        serializer = serializers.GameSerializer(data=request.data)
        serializer.is_valid(raise_exception=True)
        serializer.save()
        return Response(serializer.data, status=status.HTTP_201_CREATED)

1 Answer

Bapi Roy
Bapi Roy
14,237 Points

You forgot to import "status" from rest_framework on the top