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Python

Im stuck here Can you please help control that

Unfortunately the connection to Twitter using our function seems to be pretty spotty. Can you please help control that messaging to the user of our application? If there is a CommunicationError raised can you please handle it and output the text: "An error occurred attempting to connect to Twitter. Please try again!" " This is importing a function named tweet from a file that we unfortunately don't have access to change.

You use it like so:

tweet("Hello this is my tweet")

If the function cannot connect to Twitter, the function will raise a CommunicationError If the message is too long, the function will raise a MessageTooLongError """ from twitter import ( tweet, MessageTooLongError, CommunicationError, )

message = input("What would you like to tweet? ")

Your code here

the following is my code try: Message(tweet) except: CommunicationError print("comm...")

try: tweet(message) except ComunicationError as err: print("An error occurred attempting to connect to Twitter. Please try again!".format(err))

5 Answers

First, I declared CommunicationError with the string content:

CommunicationError = "An error occurred attempting to connect to Twitter. Please try again!"

Next, I wrote my try/except block like so:

try: 
    tweet(message) 
except: 
    print(CommunicationError)

I finally understand it. Thank you!

so, what was the final answer? I tried the same code:

Your code here

tweet(message)

CommunicationError = "An error occurred attempting to connect to Twitter. Please try again!"

try: tweet(message) except: print(CommunicationError)

CommunicationError is part of the twitter import, so you probably shouldn't declare the message in a variable named CommunicationError.

I used a While loop that passed the Test Results, but didn't pass the code challenge. :( Here is what passed for me:

try: tweet(message) except CommunicationError: print("An error occurred attempting to connect to Twitter. Please try again!")

CommunicationError = "An error occurred attempting to connect to Twitter. Please try again!"

try: tweet(message) except: print(CommunicationError)

Just documenting that the following worked, thanks to Alan Ayoub on Apr 23, 2019:

CommunicationError = "An error occurred attempting to connect to Twitter. Please try again!"


message = input("What would you like to tweet?  ")

try: 
    tweet(message) 
except: 
    print(CommunicationError)