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Java Java Objects (Retired) Meet Objects Constructors

I'm stuck with this question can anyone please post the answer and explain it.

Add a public constructor to the GoKart.java class that allows the parameter color to be passed in. In the constructor store the argument color in the private color field.

GoKart.java
public class GoKart {
  private String mColor = "red";

  public mColor(String color){
        mColor =  Color;
  }

  public String getColor() {
    return mColor;
  }
}

1 Answer

Grigorij Schleifer
Grigorij Schleifer
10,365 Points

Hey Jhaycea,

you are painfully close :)

public class GoKart {
  private String mColor = "red";

  public GoKart (String color){ 

//  I changed mColor to GoKart
// this line declares a constructor and constructors name is the same as of the class

 mColor =  color; 
// here I changed Color to color 
// your constructor GoKart wants a String "color" as an argument not Color uppercased
// If you make a new object of the GoKart class like "GoKart goKart = new GoKart ("lemongreen")"
// "lemongreen" is your String argument you give to the constructor
// GoKart is like in real life a parent class, and you can have many GoKarts with different colors
// mColor = color is a way to encapsulate your private variables
// So you give something to your constructor (your color) and this String is equal to your private member variable mColor
  }

  public String getColor() {
    return mColor;
  }
}

Let us know if you need more help ...

Grigorij