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JavaScript AJAX Basics (retiring) AJAX and APIs Call the jQuery $.getJSON method

Marcin Robert Kaźmierczak
Marcin Robert Kaźmierczak
33,570 Points

I'm stucked on the Final AJAX challenge...

$(document).ready(function() {
  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"
  };
  function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);
    $.getJSON(weatherAPI, weatherReport, data);
  }

});

1 Answer

Marcin Robert Kaźmierczak
Marcin Robert Kaźmierczak
33,570 Points

Ok. I've got it :) There was an error with the JSON function and placement of this function. Final code is:

$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"
  };

  function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);

  }
  $.getJSON(weatherAPI, data, showWeather);  
});
Alan Fidelino
Alan Fidelino
12,846 Points

Thanks. I actually made a mistake of passing the 3rd parameter - showWeather as showWeather(), hence my code didn't work.