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Python

Posted by Austin March
Austin March
2,310 Points

Im trying to only accept integers with a value of 1 to 10. Nothing seems to work.

day.py is my code: https://w.trhou.se/n1xdfv5220 I think that my issue is with the list[ ] but im not sure. I want to accept values 1 thru 10, but reject all values like '100', or a letter like 'T'. It is hard to compare values after i ask the question because the value they enter has to be a string, but i want an integer. There are only 1 way i think i can do it:

except only integers and tell the user if they try and input a letter that its invalid. Then filter filter the integer they input to only accept it if its between 1 and 10.

I dont know how to use functions for this purpose, so help would be appreciated. thanks in advance.

4 Answers

Cooper Runstein
Cooper Runstein
11,851 Points
Cooper Runstein
Cooper Runstein
11,851 Points

Nice work so far! Your problem is your comparision

my_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
scale = input("On a scale of 1 - 10, how is your day going?  ")
if scale == my_list:  # if scale (an input) is equal to the *entire* list.
    print("Valid!")
    exit()
elif scale != my_list # if scale (an input) is not equal to the *entire* list.
    print("Invalid!")
print("end of script")

What you want to do is check if scale is in the list:

my_list = ['a', 'b', 'c']
my_letter = 'a'
my_letter == my_list #false
my_letter in my_list #true

The way the iteration short cut in works is similar to doing this:

my_list = ['a', 'b', 'c']
my_letter = 'a'
for letter in my_list:
    if my_letter == letter:
        return True
    return False

Finally, for this case, what you're doing is perfect, but for more complex examples, you'll need to learn how to use try/except blocks. These will allow you to take any input and test to make sure it fits your parameters. Check out https://docs.python.org/3/tutorial/errors.html or part 3 of this course: https://teamtreehouse.com/library/python-basics-3

Hope that helps, and maybe gives a bit of insight into your code. Let me know if I can answer anything left unanswered!

Cooper Runstein
Cooper Runstein
11,851 Points

Also to directly answer your question as to how to only accept integers:

scale = input('Give me a number between 1 and 10)
try:
    scale = int(scale)
except ValueError:
    print('Not a valid number')
Austin March
Austin March
2,310 Points

https://w.trhou.se/soak0s2sia doesnt it works, but it displays the message like 5 times... dont know why. thank you so much! also how do i get that type of workspace? i like the U.I. better

Cooper Runstein
Cooper Runstein
11,851 Points
Cooper Runstein
Cooper Runstein
11,851 Points

I'm not sure what you mean about workspaces, but here's whats going on with your code:

for my_number in my_list: #for every number in my list
    if str(scale) >= "6": //For the condition that is true, do whatever
        print("Happy. CHANGE THIS LATER")
    elif str(scale) <= "5":
        print("Sad. CHANGE THIS LATER")
    else:
        print("That's not a valid number! Try again later.")

You don't need the for loop, because your if statement does all the work and doesn't depend on my_list

Austin March
Austin March
2,310 Points

i fixed it with another method, and now everything works the way i need it to, except when i enter 10. I think it is with my comparisons with the == and <= and >= or something similar, but i dont know why it says 10 is a sad number. only numbers 5 or under should be sad. link: https://w.trhou.se/nk9ebg8qxn

Cooper Runstein
Cooper Runstein
11,851 Points

I'm on a phone, not a computer, so I haven't tested it yet, but I would image that it has something to do with your handling of types. You're turning scale into an integer, but then comparing to to strings.

int(scale)  == '5' #left side is an int, right is a stripg
Austin March
Austin March
2,310 Points
Austin March
Austin March
2,310 Points

fixed the str to int errors. not the issue. must be something else. also, im in school no rush for an answer

Cooper Runstein
Cooper Runstein
11,851 Points
Cooper Runstein
Cooper Runstein
11,851 Points 
my_list = [1,2,3,4,5,6,7,8,9,10]
def test_for_mood(mood): #create a function to store your logic that takes a single input
    try: 
        mood = int(mood) #turn the mood (the function's input) into an integer if possible
    except ValueError: #if it isn't we can end the program
        print("Nope, that isn't a number") 
        exit()
    if mood in my_list: #check if the number is in the list of valid numbers
        if mood >= 6: #If the number is happy
            print('Happy')
        elif mood <= 5: #if not
            print('Sad')
    else: 
#if the number wasn't in the list of numbers. No need to test for the number bigger than 10, this else catches that.
        print('That number is not valid')
        #The function ended successfuly
    print('Done')
scale = input('how was your day 1-10') #get the number
test_for_mood(scale) #pass the number into your logic function

This is what I would do. I'm not sure how experienced you are with functions, but a function would make your code a lot easier to troubleshoot.

Also, just so you know, you can use the range function (https://docs.python.org/3/library/functions.html#func-range) instead of creating a list of numbers between 1 and 10 like so:

my_list = range(1, 11) #up to, but not including 11

If any of this, either the function part or the range is too much for you to grasp at this point, don't worry about it, just knowing that those options exist will help you out as you're learning in the future. Just let me know if you have any more questions!

Austin March
Austin March
2,310 Points

list is easier for this amount of numbers, because i want 5, not like 5.5. thank you. it works now! A little too advanced for me, but im getting there

Cooper Runstein
Cooper Runstein
11,851 Points

Actually, unless specified otherwise, range will only print out integers (whole numbers). So:

for x in range(1, 11):
    print(x)
#1
#2
#3
...
#10