Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialAustin Miller
5,171 PointsI'm very lost on how I need use the loop and the if statement...
I have no idea what to do through from lines 7 - 11. I feel like I just don't understand if my loop is right and what to put in my if statement.
public class ScrabblePlayer {
// A String representing all of the tiles that this player has
private String tiles;
public int getCountOfLetter(char letter) {
int count = 0;
for (char newLetter : tiles.toCharArray()) {
if () {
++count;
}
}
return count;
}
public ScrabblePlayer() {
tiles = "";
}
public String getTiles() {
return tiles;
}
public void addTile(char tile) {
tiles += tile;
}
public boolean hasTile(char tile) {
return tiles.indexOf(tile) != -1;
}
}
// This code is here for example purposes only
public class Example {
public static void main(String[] args) {
ScrabblePlayer player1 = new ScrabblePlayer();
player1.addTile('d');
player1.addTile('d');
player1.addTile('p');
player1.addTile('e');
player1.addTile('l');
player1.addTile('u');
ScrabblePlayer player2 = new ScrabblePlayer();
player2.addTile('z');
player2.addTile('z');
player2.addTile('y');
player2.addTile('f');
player2.addTile('u');
player2.addTile('z');
int count = 0;
// This would set count to 1 because player1 has 1 'p' tile in her collection of tiles
count = player1.getCountOfLetter('p');
// This would set count to 2 because player1 has 2 'd'' tiles in her collection of tiles
count = player1.getCountOfLetter('d');
// This would set 0, because there isn't an 'a' tile in player1's tiles
count = player1.getCountOfLetter('a');
// This will return 3 because player2 has 3 'z' tiles in his collection of tiles
count = player2.getCountOfLetter('z');
// This will return 1 because player2 has 1 'f' tiles in his collection of tiles
count = player2.getCountOfLetter('f');
}
}
1 Answer
Steven Parker
231,268 PointsYou're really close! The loop is fine, and all you need yet is to add an expression in the "if" that compares the tile letter with the argument:
if (newLetter == letter) {
Austin Miller
5,171 PointsAustin Miller
5,171 PointsThank you! I thought it had to be
if (newLetter.equals(letter)). I didn't think == would work
Steven Parker
231,268 PointsSteven Parker
231,268 PointsYou're absolutely right, I was thinking in another language there!
It does happen to pass in the challenge, but the correct test would be as you suggest:
if (newLetter.equals(letter)) {
Brendon Butler
4,254 PointsBrendon Butler
4,254 PointsSteven Parker Just a heads up, it's always best practice to use
.equals()
when comparing strings in Java..equals()
only compares the exact text contained in the variable.==
compares the entire variable/instance. Which can cause the output to be false even if "newLetter" and "letter" were both equal to say "e".Steven Parker
231,268 PointsSteven Parker
231,268 PointsGood point. A "==" is a reference equality test, but ".equals()" is a value equality test which is what should be used in this case.