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JavaScript JavaScript Basics (Retired) Working With Numbers Numbers and Strings

mohammed mayat
mohammed mayat
4,228 Points

Imagine you have 10 <div> tags on a web page. Each div is 190 pixels wide. Using the two variables in this script, creat

I have tried a lot of different answer I am 90% sure the last one is correct, it is still saying bummer

app.js
var width = '190px';
var numOfDivs = 10;
//var width = '190px'; var numOfDivs = 10; 
//var totalWidth = 'parseInt(width)' * 'numOfDivs';
var totalWidth = 'parseInt(width)' * 'parseInt(numOfDivs)';
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="app.js"></script>
</body>
</html>

2 Answers

Huzaifa Sajjad Malik
PLUS
Huzaifa Sajjad Malik
Courses Plus Student 10,823 Points
var width = '190px';
var numOfDivs = 10;
//var width = '190px'; var numOfDivs = 10; 
//var totalWidth = 'parseInt(width)' * 'numOfDivs';
var totalWidth = 'parseInt(width)' * 'parseInt(numOfDivs)';//here you are treating both the var as strings you have wrapped them in strings.
Solution:
var totalWidth=parseInt(width) * numOfDiv;
//You Parse strings only so that they are converted to the relevant data-type
mohammed mayat
mohammed mayat
4,228 Points

thanks for the quick reponse, still not working

var width = '190px'; var numOfDivs = 10;

var totalWidth = 'parseInt(width)' * 'numOfDivs';

Huzaifa Sajjad Malik
PLUS
Huzaifa Sajjad Malik
Courses Plus Student 10,823 Points

Bro why are you wrapping the parseInt(width) and numOfDivs in string quotes ' ' just type them without quotes like this just copy and paste this code in the code challenge :) Peace.

var width = '190px';
var numOfDivs = 10;
var totalWidth=parseInt(width)*numOfDivs;
Peter B. Sims
Peter B. Sims
Courses Plus Student 2,896 Points

Thanks for keeping it simple, Huzaifa Sajjad Malik. Peace