Tyler Lundgren
Pro Student 5,439 PointsIn the body of my function, how do I return a squared number?
def square (number): return number * 2....?????
def square (number):
return number * 2 !=
KRIS NIKOLAISEN
Pro Student 51,979 Pointsnoob developer needs to post answers not comments
3 Answers
<noob />
16,701 PointsHi!, your really close, the right code is this:
def square(number):
return number*number
like u see first, i created a function named square and pass a paramater named number. to return a squared number *** YOU NEED TO MULTIPLY THE NUMBER BY HIM SELF*** and not by 2, and because of that u need to retun number*number.
if that answer has halped mark as best answer in order to close this article :D
Mark Nembhard
649 PointsPlease help. I think this is correct but it keeps coming up error on line 4 "" end of file. See below. def square(number): square = number*number return square number = int(input("input the number you would like squared")) result = square(number) Print (" your number squared is {}".format(result))
<noob />
16,701 PointsMark Nembhard the correct answer is above
Mark Nembhard
649 PointsIv'e done that. the code is returning an error still
<noob />
16,701 Points<noob />
16,701 PointsHi!, your really close, the right code is this:
like u see first, i created a function named square and pass a paramater named number. to return a squared number *** YOU NEED TO MULTIPLY THE NUMBER BY HIM SELF*** and not by 2, and because of that u need to retun number*number.
if that answer has halped mark as best answer in order to close this article :D