Tyler Lundgren
Pro Student 5,203 PointsIn the body of my function, how do I return a squared number?
def square (number): return number * 2....?????
def square (number):
return number * 2 !=
KRIS NIKOLAISEN
Pro Student 44,772 Pointsnoob developer needs to post answers not comments
3 Answers
bot .net
11,466 PointsHi!, your really close, the right code is this:
def square(number):
return number*number
like u see first, i created a function named square and pass a paramater named number. to return a squared number *** YOU NEED TO MULTIPLY THE NUMBER BY HIM SELF*** and not by 2, and because of that u need to retun number*number.
if that answer has halped mark as best answer in order to close this article :D
Mark Nembhard
387 PointsPlease help. I think this is correct but it keeps coming up error on line 4 "" end of file. See below. def square(number): square = number*number return square number = int(input("input the number you would like squared")) result = square(number) Print (" your number squared is {}".format(result))
bot .net
11,466 PointsMark Nembhard the correct answer is above
Mark Nembhard
387 PointsIv'e done that. the code is returning an error still
bot .net
11,466 Pointsbot .net
11,466 PointsHi!, your really close, the right code is this:
like u see first, i created a function named square and pass a paramater named number. to return a squared number *** YOU NEED TO MULTIPLY THE NUMBER BY HIM SELF*** and not by 2, and because of that u need to retun number*number.
if that answer has halped mark as best answer in order to close this article :D