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JavaScript Node.js Basics 2017 Handling Errors in Node Using try and catch

Posted by Thomas Ma
Thomas Ma
15,199 Points

In the catch block, call console.error to print out the error's message property.

Please give me an answer.

app.js 
const jsonString = 'This is not a JSON String';
const jsonObject = JSON.parse(jsonString);
try {
 var jsonString = 'This is not a JSON String';
try {
  var jsonObject = JSON.parse(jsonString);
} catch(error) {
  console.error(error.message);
}
}; catch (error) {

}

1 Answer

Michael Kobela
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Michael Kobela
Full Stack JavaScript Techdegree Graduate 19,570 Points
Michael Kobela
.a{fill-rule:evenodd;}techdegree seal-36
Michael Kobela
Full Stack JavaScript Techdegree Graduate 19,570 Points

The code had a extra ; before the last catch, try this:

const jsonString = 'This is not a JSON String';
const jsonObject = JSON.parse(jsonString);
try {
  var jsonString = 'This is not a JSON String';
  try {
    var jsonObject = JSON.parse(jsonString);
   } catch (error) {
      console.error(error.message);
  }
} catch (error) {

}
Kri'Shawn Brown
Kri'Shawn Brown
10,452 Points

get rid of the first try statement and second catch statement and that will work