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CSS Sass Basics (retired) Advanced Sass Concepts Interpolation and if/else Loops

Include Mixin inside Mixin

Can I inside mixin in other mixin? I have a mixin for radius and a mixin for prefixr and I need use de prefixr mixin first but inside put the radius. Is that posible?


@include prefixr({ @include radius(), value})

2 Answers

Hey Luis

You can do something like this...

@mixin a {
  mixin goes here
@mixin b {
  @include a();

  other stuff goes here


Kleo Petroff
Kleo Petroff
5,726 Points

Hi Matt, I can actually include a mixin without the parentheses. What is the better way of doing it - with or without them?

Hey Kleo

I would still include the brackets. Some mixins require variables and this would go between the brackets so its a good habit to get into.

For example mixin would be...

@mixin border-radius($radius) {
  border-radius: $radius;

and then include the mixin...

@include border-radius(10px);