Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Jonathan Bravo
Jonathan Bravo
19,072 Points

Incorrect Output?

I have run this code multiple times in a terminal and I get the correct output. What could be causing incorrect output?

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
  string = string.lower()
  string = list(string.split(' '))
  d = {}
  for word in string:
    d[word] = string.count(word)
  return d
Jonathan Bravo
Jonathan Bravo
19,072 Points

Ended up working by just doing the second suggestion. Thanks so much!

1 Answer

Couple of things:

  1. You need to change d[word] = string.count(word) to an if statement if word in d: d[word] += 1 else: d[word] = 1
  2. Remove the ' ' in split(' ') - this should work regardless but not in this course