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yige yang
8,329 Pointsindex.of problem .java
how to solve this problem and how does it happen. THANK YOU.
public class ScrabblePlayer {
// A String representing all of the tiles that this player has
private String tiles;
public ScrabblePlayer() {
tiles = "word";
}
public String getTiles() {
return tiles;
}
public void addTile(char tile) {
tiles += tile;
}
public boolean hasTile(char tile) {
boolean hasTile = tiles.indexOf(tile) != -1;
return true;
}
}
2 Answers
Tonnie Fanadez
UX Design Techdegree Graduate 22,796 PointsHello yige yang
You did the first challenge well, impressive!!
This is how I approached the second problem. I first created a boolean hasLetter and I set it to false. I then went for the for-loop to iterate through the characters contained inside tiles. I used String.toCharArray().length method to convert the tiles to an array of characters and get the number of letters.
Lastly, I used String.indexOf( char) which returns -1 if the character is not found, if character is found, it returns a number that is greater or equal to zero.
public boolean hasTile(char tile) {
// TODO: Determine if user has the tile passed in
boolean hasLetter = false;
for(int i =0; i<tiles.toCharArray().length; i++){
hasLetter = ( tiles.indexOf(tile) >=0);
}
return hasLetter;
}
Tonnie Fanadez
UX Design Techdegree Graduate 22,796 PointsYou can also use for-each loop for this problem:
public boolean hasTile(char tile) {
// TODO: Determine if user has the tile passed in
boolean hasLetter = false;
for(Character letter: tiles.toCharArray()){
hasLetter =tiles.indexOf(tile)>=0;
}
return hasLetter;
}