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iOS Swift 2.0 Collections and Control Flow Control Flow With Conditional Statements FizzBuzz

sai jayanth kashyap
sai jayanth kashyap
3,293 Points
Posted by sai jayanth kashyap
sai jayanth kashyap
3,293 Points

int to string type

swift_lint.swift:16:17: error: cannot convert return expression of type 'Int' to return type 'String' return (n) ~^~

I am having this trouble , i don't know how to cover this.

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
   for n in 1...100 {
        if (n % 3 == 0) && (n % 5 == 0){
            return ("FizzBuzz")
        }
        else if (n % 3 == 0){
            return("Fizz")
        } 
        else if (n % 5 == 0){
            return ("Buzz")
        } 
        else {
        return (n)
        }


    }

  // End code
  return "\(n)"
}

2 Answers

agreatdaytocode
agreatdaytocode
24,757 Points
agreatdaytocode
agreatdaytocode
24,757 Points

Hello sai jayanth kashyap

For this challenge you don't need a for loop. Try the following for me, and please let me know if you have any questions. 

func fizzBuzz(n: Int) -> String {
  if (n % 3 == 0) && (n % 5 == 0) {
    return "FizzBuzz"
  } else if (n % 3 == 0) {
    return "Fizz"
  } else if (n % 5 == 0) {
    return "Buzz"
  }

  return "\(n)"
}