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Mladen Milinkovic
14,246 Points$integerOne = 1; &integerTwo = 2; Add 5 to $integerOne. Subtract 1 from $integerTwo. Help?!
Need solution, I can't find mistake in my code.
<?php $integerOne = 1; &integerTwo = 2; var_dump($integerOne + 5); var_dump($integerTwo - 1); ?>
<?php
//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
echo($integerOne + 5);
echo($integerOne - 1);
?>
3 Answers

james south
Front End Web Development Techdegree Graduate 33,258 Pointsyou don't need to echo anything, they just want you to change the value of your variables. adding/subtracting like you are is not actually reassigning the new values to the variables. for that you simply need to put myVar = myVar + 5 etc., or even more simply, use the += and -= shortcuts, so myVar += 5, etc.

Mladen Milinkovic
14,246 PointsThanks!!!

Aigars Kalvans
3,815 PointsAnswer $integerOne=1; $integerTwo=2; $integerOne=1 + 5; $integerTwo=2 - 1;