Java Java Data Structures Organizing Data Comparable

Interface challenge part 3

3rd part of the challenge asks to make a chronological order, but oldest should be first, how do you do the reverse of Arrays.sort ?

com/example/BlogPost.java
package com.example;

import java.util.Date;

public class BlogPost {
  private String mAuthor;
  private String mTitle;
  private String mBody;
  private String mCategory;
  private Date mCreationDate;

  public BlogPost(String author, String title, String body, String category, Date creationDate) {
    mAuthor = author;
    mTitle = title;
    mBody = body;
    mCategory = category;
    mCreationDate = creationDate;
  }

  public String[] getWords() {
    return mBody.split("\\s+");
  }

  public String getAuthor() {
    return mAuthor;
  }

  public String getTitle() {
    return mTitle;
  }

  public String getBody() {
    return mBody;
  }

  public String getCategory() {
    return mCategory;
  }

  public Date getCreationDate() {
    return mCreationDate;
  }
}
Steven Parker
Steven Parker
171,342 Points

Please update this code to show the work you have done for tasks 1 and 2, plus any you have begun for task 3.

1 Answer

Steven Parker
Steven Parker
171,342 Points

You don't actually do any sorting for this challenge. But the compareTo() method should return either a negative or a positive value depending on whether the first object is less or greater than the second. The challenge is telling you to use the creation date as the basis for making that determination.

Hint: The date's own "compareTo" method could be useful.

Sorry, was inactive for few days. Thanks for the help! Now I understand it.