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iOS

Posted by Diego Aguirre
Diego Aguirre
13,211 Points

Intermediate Swift 2 protocol extensions. My answer does not seem to satisfy the test.

Here's the question:

In the editor, you've been provided with a protocol, Math, that contains a single requirement - a method that computes the square of a value. Your task is to provide a default implementation for the method through a protocol extension.

And here's my answer : 

protocol Math {
  func square(value: Double) -> Double
}

// Enter your code below

 extension Math {
    func square(value: Double) -> Double {
          return square(value)
    }
 }

1 Answer

Jeroen de Vrind
Jeroen de Vrind
29,772 Points

You created what they call a 'recursive function'. This means that the default implementation of your square method calls itself over and over again, because in the return statement you call the same method again. If you put 

return value*value

instead, it will work.

Diego Aguirre
Diego Aguirre
13,211 Points

Ha, I didn't even notice that I was calling the function within itself. I actually assumed that square was fundamental math method on Int's that I could call.

Awesome, thank you so much Jeroen!