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Russell Comer
26,102 PointsIntro to Programming Control Structures extra Credit
Any one having issues with this portion? I'm trying this but I keep getting an error not sure what syntax I have wrong any help is greatly appreciated!
var counter = 100;
while (counter > 0){
console.log(counter);
var mod1 = counter % 3;
var mod2 = counter % 5;
if (mod1 == 0, && mod2 == 0){
console.log("fizzbuzz");
}
else (mod1 == 0){
console.log("fizz");
}
else (mod2 == 0){
console.log("buzz");
}
counter = counter --;
}
2 Answers
Jeffery Briggette
Courses Plus Student 5,567 PointsI noticed that you had a comma after the && and it will give you an unexpected '&&'. This is what I came up with after reviewing your code. Hope this helps.
for (var number = 0; number <= 100; number++){
var fizz = number % 3;
var buzz = number % 5;
if (fizz == 0 && buzz == 0) {
console.log("fizzbuzz");
} else if (buzz == 0 ) {
console.log("buzz");
} else if (fizz == 0) {
console.log("fizz")
} else {
console.log(number);
}
}
Sorry, the above code is not formatting correctly for some reason. : (
Arthur Crocquevieille
15,612 PointsHey, you should replace your else statements with else if statements, because you cannot test for a condition in an else statement :)
Hope it helps :)