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JavaScript Introduction to Programming Functions Functions

Thiago de Bastos
Thiago de Bastos
14,556 Points
Posted by Thiago de Bastos
Thiago de Bastos
14,556 Points

Intro to Programming: Functions

Hey guys! I am trying to get the Extra credit done. What I want to add to this is the ability for the user to input the two values. It is late at night and I can't get my mind around it!

var evenOdd = function (b, c) {
  var a = b + c;
  if (a % 2 === 0) {
    return "even";
  } else {
    return "odd";
  }
}
console.log(evenOdd(1, 2));

This is what I have tried but can't get it to work:

var evenOdd = function (b, c) {
  var a = b + c;
  if (a % 2 === 0) {
    return "even";
  } else {
    return "odd";
  }
}
console.log(evenOdd(prompt("Enter a number"), prompt("Enter another number")));

For some reason I am getting odd or even based only on the last entered input. eg if I enter 1, 1 I get odd. If I enter 1, 2 I get even!

2 Answers

Nemanja Pribilovic
Nemanja Pribilovic
5,366 Points

you have to parseInt result from prompt parseInt(b) parseInt(c)

Nemanja Pribilovic
Nemanja Pribilovic
5,366 Points

because you get string from prompt and you need to convert it to number

Dave McFarland
Dave McFarland
Treehouse Teacher
Dave McFarland
Dave McFarland
Treehouse Teacher

Nemanja Pribilovic is right. If you type in 1 in the first prompt, then 2 in the second prompt, your JS code is going to do this

var a = "1" + "2"; // the result is 12, because this combines the 2 strings into one, bigger string.

You want to do this

var a = parseInt(a,10) + parseInt(b,10); // this will be 1 + 2  and will result in 3

The 10 in the parseInt() method is called a radix and makes sure the number is treated as a base ten, or decimal integer (instead of like an octal or hexadecimal value.